Calculate the pH of 0.2 M NaOH
Calculate the pH of 0.2 M NaOH
NaOH is a strong base, so [OH-] is the same as the concentration of the NaOH itself (it dissolves 100%).
pOH = -log[OH-]
and then pH = 14 – pOH.
The answer is 13.3
Check me out: http://www.chemistnate.com
Very helpful for me
I must inform you, that if I already knew how to do this, I would have clicked on the video. Will not be watching any more of your videos because the last thing I need while studying is being told "you should already know something that you don’t know". Thanks, guy.
Nicely explained – Thanks
Thanks man
"it’s your job to know…" Is never what I’m looking for in a how to video . . .
Found this video right after the exam 😑
Not a fan of being told what my job is, but I like te video overall. Appreciate the joke at the end!
im so dumb, i forgot completely the diffrence between pH and pOH, thanks for the help!!
Cheers
In final exam.. this ploblem is made. But i couldn’t solve the problem,,
I wish i’d known this better
Very good
Great
Thanx! this helped a lot 🙂
I like the way you presenting man !😂
Sir please can you use this method to solve for HCL
That is so basic! So am I. LOL
Thnaks!
What about 3.0 molar. It doesn’t work
Where did you get the 14 there?😅